Rounding

You are given a real number $x$. Round it to the nearest integer. If $x$ lies exactly halfway between two integers (fractional part $0.5$), round away from zero: $2.5 \to 3$, $-2.5 \to -3$, $0.5 \to 1$.

A single number $x$ ($|x| \le 10^9$) with at most 2 digits after the decimal point; the point may be absent (for example, 7).

A single integer — $x$ rounded.

Python's round() uses a different rule: it rounds a halfway value to the even neighbour — round(2.5) $= 2$, round(0.5) $= 0$. That is wrong for this problem. C++ round() and Go math.Round follow exactly this problem's rule. You can also do it by hand: take the integer part of $|x| + 0.5$ and restore the sign of .