Reverse a three-digit number

You are given a three-digit number $n$. Find the number obtained by writing its digits in reverse order.

A single integer $n$ ($100 \le n \le 999$).

A single integer — the reversed number. Leading zeros are not written: for $120$ the answer is $21$.

The hundreds digit is $n / 100$, the tens digit is $(n / 10) \bmod 10$ and the units digit is $n \bmod 10$ (integer division). The reversed number is units + tens + hundreds.